# “20-20” Quantitative Aptitude | Crack SBI Clerk / IDBI Executive 2018 Day-46

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Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk / IDBI Executive 2018 . Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.

“20-20” Aptitude Questions | Crack SBI Clerk / IDBI Executive 2018 Day-46

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 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Logical Reasoning 10.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM Static GK Quiz 1.00 PM English Language “20-20” 2.00 PM Banking Awareness Quiz 3.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM General / Financial Awareness Quiz 9.00 PM

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1. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
1. 8.30 am
2. 9.00 am
3. 10.00 am
4. 10.30 am
5. 10.45 am
1. A profit of Rs 1200 is made by selling an article if one-third of it is sold at 9% profit and the remaining at 3% loss. What is the cost price of the article?
1. Rs.180000
2. Rs.150000
3. Rs.160000
4. Rs.120000
5. None of these
1. How much litres of water should be added to 45 litres of mixture containing milk and water in the ratio of 2: 1 such that the resultant mixture has 40 % water in it?
1. 10 litres
2. 5 litres
3. 12 litres
4. 8 litres
5. None of these
1. A, B and C invested in the ratio of 3:5:7 and the profits earned by them are in the ratio of 2: 5: 8. Find the ratio of the period they invested the amount?
1. 14: 21: 24
2. 3: 7 : 9
3. 11: 15: 18
4. 4 : 6 : 9
5. None of these
1. 5 years hence, Rahul and Ravi’s age ratio will be 3: 4. The present age of Rahul is equal to Ravi’s age 10 years ago. Find the Present age of Rahul and Ravi?
1. 20, 30
2. 35, 45
3. 25, 35
4. 15, 25
5. None of these

Directions (Q. 6-10): What should come in place of question mark (?) in the following number series?

1. 5, 35, 91, 181, 313, ?
1. 542
2. 495
3. 381
4. 614
5. None of these
1. 1536, 192, 32, ? , 4
1. 16
2. 12
3. 24
4. 8
5. None of these
1. 53, 153, 604, 3010, ?
1. 9830
2. 15678
3. 18048
4. 8564
5. None of these
1. 13, 16, 25, 52, ?
1. 96
2. 133
3. 84
4. 198
5. None of these
1. 27, 55, 174, 721, ?
1. 1024
2. 2768
3. 1782
4. 3654
5. None of these

Directions (Q. 11–15): What value should come in the place of question mark (?) in the following questions?

1. {(135)2 ÷ 15 × 39} ÷? = 60 × 52
1. 12.2575
2. 15.1875
3. 18.5056
4. 16.2550
5. None of these
1. 1272 ÷ ? = 1382 – 956 – 214
1. 9
2. 3
3. 6
4. 8
5. None of these
1. 444 ÷ 12 × 28 – 724 +112 =?
1. 256
2. 348
3. 198
4. 424
5. None of these
1. 3/8 of 4/9 of 1575 + (√?) – 32% of 786 = 66.98
1. 1296
2. 56
3. 3136
4. 36
5. None of these
1. 97336 +6889 ÷ 2?– 3/4 of 65 + 52 = 43
1. 4
2. 16
3. 8
4. 2
5. None of these

Directions (Q. 16 – 20): Study the following table and answer the questions that follow:

The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married. 1. Approximately what percentage of females in department B is less than that in department C?
1. 8%
2. 10%
3. 11%
4. 12%
5. 15%
1. How many males in department D are married?
1. 256
2. 265
3. 243
4. 234
5. 208
1. What is the difference between the total number of females in department A and number of males in department B, who are all unmarried?
1. 32
2. 34
3. 36
4. 38
5. 48
1. What is the total number of males in departments D and E?
1. 605
2. 705
3. 505
4. 405
5. None of these
1. What is the ratio of number of unmarried males in department C to number of married males in department B?
1. 29 : 26
2. 26: 29
3. 23: 27
4. 27: 23
5. None of these

Both the trains meet at x hours after 7 am,

Distance covered by A in x hours = 20x km

Distance covered by B in (x-1) hours = 25(x-1) km

20x + 25(x-1) = 110

20x + 25x -25 =110

45x = 135

X = 135/45 = 3

1st train meets second train after 3 hours = > 3 +7 = 10 am

Let cost price be x,

Profit = 1200 = Sp – Cp

[X*(1/3)*(109/100) + x*(2/3)*(97/100)] – x = 1200

109x +194x -300x = 360000

3x = 360000

X = 120000

Total mixture = 45 litres

Milk: water = 2: 1

3’s = 45

1’s = 15

Milk = 30 lit, Water = 15 lit

30/(15+x) = 60/40

30/(15+x) = 3/2

20 = 15+x

X = 5 litres

So 5 litres of water should be added

Investment ratio = > 3:5:7

Profit ratio = > 2:5:8

Period = > (2/3): (5/5): (8/7)

= > 70: 105: 120

= > 14: 21: 24

5 years hence, Rahul and Ravi’s age ratio will be 3: 4 (3x, 4x)

Present age of Rahul and Ravi = 3x-5, 4x-5

The present age of Rahul is equal to Ravi’s age 10 years ago

3x-5 = 4x-15

X = 10

Present age of Rahul and Ravi = 3x-5, 4x-5 = 25, 35

Directions (Q. 6-10):

The difference is, 62-6, 82-8, 102-10, 122-12, 142 -14…

The pattern is, ÷ 8, ÷ 6, ÷ 4, ÷ 2

The pattern is, *3-6, *4-8, *5-10, *6-12…

The difference is, 3, 32, 33, 34

The pattern is, *2+12, *3+32, *4+52, *5+72, *6+92

Directions (Q. 11–15):

(135 ×135× 39)/15 ÷ x = 60 × 52

X = (135 ×135× 39)/(15×60 × 52)

X = 15.1875

1272/x = 1382 – 956 – 214

X = 1272/ 212

X = 6

(444/12) × 28 – 612 = x

X= 1036 – 612

X= 424

3/8 × 4/9 × 1575 + (√?) – 32% of 786 = 66.98

1/2 × 525 + (√?) – (32/100) × 786 = 66.98

262.5 + (√?)– 251.52 = 66.98

262.5 – 251.52 + (√?) = 66.98

(√?)  = 56

? = (56)2 = 3136

∛97336 +√6889 ÷ 2?– 3/4 of 65 + 52 = 43

46 + 83/2x – 48.75 + 25 = 43

83/20.75 = 2x

4 = 2x = > 22 = 2x

x = 2

Directions (Q. 16 – 20):

Females in department B = (40/100)*290 = 116

In department C = (35/100)*360 = 126

Required % = (126-116)/126 * 100 ≈ 8%

3/5 * (75/100) * 540 = 243

Females in A = (20/100)*450 = 90

Males in B who come are unmarried = (1/3) * (60/100)*290 = 58

Difference = 90 – 58 = 32

D + E = (75/100)*540 + (80/100)*250 = 405 + 200 = 605

Unmarried males in department C = (4/9) * (65/100)*360 = 104

Married Males in department B = (2/3) * (60/100)*290 = 116

104: 116 = 26: 29