# “20-20” Quantitative Aptitude | Crack SBI Clerk / IDBI Executive 2018 Day-48

Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk / IDBI Executive 2018 . Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.

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Directions (Q. 1 – 5) what value should come in the place of question mark (?) in the following number series?

1. 378, 190, 49.5, ? , 5.40625
1. 11.25
2. 15.75
3. 25.25
4. 27.25
5. None of these
1. 43, 45, 93, 283, ?
1. 652
2. 758
3. 1137
4. 1256
5. None of these
1. 5, 11, 25, 51, ?
1. 78
2. 91
3. 107
4. 93
5. None of these
1. 4, 6, 15, ? , 236.25
1. 45
2. 52.5
3. 75.25
4. 81.75
5. None of these
1. 36, 39, 51, ? , 126
1. 72
2. 87
3. 95
4. 102
5. None of these

Directions (Q. 6-10): What value should come in the place of question mark (?) in the following questions?

1. (32 × 10-5)2 × 64 ÷ (216 × 10-4) = 10?
1. -4
2. -7
3. -3
4. -6
5. None of these
1. √((27 ÷ 5 ×?) ÷ 15) = 5.4 ÷ 6 +0.3
1. 12
2. 4
3. 9
4. 15
5. None of these
1. 18 ¼ % of 17200 + 33 2/3 % of 1890 +37 2/3 % of 19680 =?
1. 12658.1
2. 13377.3
3. 11188.1
4. 15678.3
5. None of these
1. [(1/57) × 3534] + (8/27) × 2484 = ? × 3
1. 356
2. 428
3. 477
4. 266
5. None of these
1. 1 ¾ + 7 5/7 – 3 7/8 + 2 ½ = x
1. 7  5/56
2. 6  3/29
3. 8  7/57
4. 5  4/37
5. None of these

1. Five years ago, the age of Kiran was half the age of Kirti. After nine years the age of Kiran will be two thirds the age of Kirti. What is the present age of Kirti?
1. 27 years
2. 30 years
3. 33 years
4. 36 years
5. 40 years
1. 8 men can finish a piece of work in 21 days. 14 men started working and after 3 days they were replaced by 9 women. These 9 women finished the remaining work in 24 days. In how many days can 9 women finish the whole work?
1. 32
2. 24
3. 42
4. 45
5. 34
1. A person covers 360 km in 6 hours. He covers some distance by bus at the average speed of 40 kmph and the remaining distance by train at the average speed 70 kmph. Find the distance covered by the train.
1. 340
2. 450
3. 240
4. 167
5. 150
1. A boat can travel 12.8 km downstream in 32 minutes. If the speed of the current is 1/5 of the speed of the boat in still water, what distance can the boat travel in 27 minutes?
1. 7.5
2. 12
3. 17
4. 9
5. 15

1. The cost price of article A is Rs 100 more than the cost price of article B. Article A was sold at 40% profit and article B was sold at 40% loss. If the overall profit earned after selling both the articles is 5% then what is the cost price of article B?
1. 320
2. 130
3. 350
4. 120
5. 650

Directions (Q. 16 – 20) Study the following graph carefully and answer the given questions:

The number of different balls in two bags A and B 1. If three balls are picked at random from bag A, What is the probability that at least one is orange?
1. 455/969
2. 514/969
3. 355/969
4. 463/969
5. None of these
1. 1 If two balls are picked at random from B, What is the probability that both balls are either white or black?
1. 3/11
2. 5/8
3. 7/8
4. 1/11
5. None of these
1. If four balls are picked at random from bag A, What is the probability that two balls are orange, one is pink and one is black?
1. 3/646
2. 5/323
3. 15/646
4. 15/323
5. None of these
1. 1 If 3 balls are picked at random from bag B, What is the probability that at most one is black?
1. 52/65
2. 64/77
3. 37/87
4. 43/65
5. None of these
1. If 4 balls are picked at random from bag B, what is the probability that all balls are of different colour?
1. 24/209
2. 15/103
3. 28/119
4. 42/103
5. None of these

Directions (Q. 1 – 5)

The pattern is, ÷ 2 + 1, ÷4 +2, ÷6 +3, ÷8 +4, ..

The pattern is, ×1 +2, ×2 + 3, ×3 +4, ×4+5

The difference of difference is, 8,12,16,..

The pattern is, ×1.5, ×2.5, ×3.5, ×4.5,..

The pattern is, +(1*3), +(2*6), +(3*9), +(4*12),..

Directions (Q. 6-10):

((32× 32) × 10-10 × 64) / (216 × 10-4) =10x

((25 × 25) × 10-10 × 26) / (216 × 10-4) =10x

10-10/ 10-4 = 10x

10-10+4 = 10x

10-6 =10x

X= -6

√((27 /5 )×(x/15)) =0.9+0.3

(3/5) √ x = 1.2

√ x = 6/3 =2

X= 4

(73/400)*17200 +(101/300)*1890 +(113/300)*19680 = x

X= 3139 +636.3 +7412.8

X = 11188.1

3 × ? = (3534/57) + [ (8 × 2484) / 27 ]

62+736 = 3x

3x = 798

X= 266

(1+7-3+2) (3/4 +5/7 -7/8 +1/2) =x

7 + [(42+40-49+28)/56] = x

7 + 61/56 = x

8  5/56 =x

Let the present age of Kiran and Kirti be x and y,

(x-5)= ½(y-5)

2x-5= y….. (i)

x +9 = 2/3(y +9)

2y- 3x=9…. (ii)

By solving we get

Y= 18+15= 33 years

8 men can do a piece of work in 21 days

So, 1 man can do the piece of work in 21*8 days

14 men can do in 3 days

1*14*3/21*8= ¼ work

Remaining work = 1-1/4= ¾

¾ work was completed by 9 women in 24 days

Total work can be completed by 9 women in 24*4/3= 32 days

Average speed of the person= 360/6= 60 kmph

By applying the rule of allegation we get, = >1 : 2

Ratio between distances covered as 1:2

So, Distance covered by train= 360*2/3=240 km

Let the speed of the boat in still water be x kmph

Speed of the current= x/5

Downstream speed = x + x/5= 6x/5

Downstream speed in kmph = 12.8*60/32= 24 kmph

So,

6x/5= 24

x = 20 kmph

Distance in 27 minutes= 20*27/60= 9 km

Profit in article A= 40%

Loss in article B= 40%

By allegation method we get ratio of cost price of both article in ratio= 9:7

Let the cost price of article A be 9x and B be 7x

So, 9x-7x= 100

x = 50

Cost price of article B = Rs 50 * 7= Rs 350

(or) = >9 : 7

2’s = 100

1’s = 50

The cost price of article B = 7’s = 350

Directions (Q. 16 – 20)

Total Probability = 19C3

Required Probability = 1- none is orange

Probability of getting none is orange= 15C3

Probability = 15C3 / 19C3  = 455/969

Probability of getting atleast one is orange= 1- (455/969) = 514/969

Total Probability = 22C2  = 11*21

Required Probability= 4C2 or 6C2 = 6+15 =21

The probability that both balls are either white or black,

= > 21/(11*21) = 1/11

Total Probability = 19C4

Required Probability= 4C2  and3C1  and 5C1

The probability that two balls are orange, one is pink and one is black,

= > (4C2  and3C1  and 5C1 ) / 19C4

= > 15/646

Total Probability = 22C3

Required Probability = 16C3 or (6C1  and16C2)

The probability that at most one is black

= >16C3 or (6C1  and16C2) / 22C3

= >(560 + 720) / 1540 = 1280/1540

= > 64/77

Total Probability = 22C4

Required Probability= 7C1  and5C1  and 4C1  and 6C1

The probability that all balls are of different colour

= > (7C1  and5C1  and 4C1  and 6C1 ) / 22C4

= > 24/209

Daily Practice Test Schedule | Good Luck

 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Logical Reasoning 10.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM Static GK Quiz 1.00 PM English Language “20-20” 2.00 PM Banking Awareness Quiz 3.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM General / Financial Awareness Quiz 9.00 PM 