# LIC AAO/SBI PO Prelims Quantitative Aptitude Questions 2019 (Day-32)

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[WpProQuiz 6104]

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Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,

a) If x > y

b) If x â‰¥ y

c) If x < y

d) If x â‰¤ y

e) If x = y or the relation cannot be established

1) I) 8x â€“ 4y = 3x â€“ 2y + 16

II) 3x + 5y + 9 = 0

2) I) x2 â€“ x â€“ 72 = 0

II) y2 â€“ 3y â€“ 88 = 0

3) I) 2x2 â€“ 38x + 156 = 0

II) 4y2 â€“ 34y + 66 = 0

4) I) x2 â€“ 16x â€“ 57 = 0

II) y2 + 20y + 75 = 0

5) I) x2 = 784

II) y2 + 15y + 56 = 0

Directions (Q. 6 â€“ 10): Study the following information carefully and answer the given questions:

The following table shows the total number of employees in 5 departments in a certain company and the % of males and the ratio of married females and unmarried females among them.

 Department Total employees % of males Married females : Unmarried females P 1250 52 % 5: 1 Q 800 68 % 5: 3 R 650 72 % 1: 1 S 1000 56 % 3: 5 T 950 44 % 3: 1

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6) Total number of female employees working in department P and S together is approximately what percentage of total number of male employees working in department Q and T together?

a) 110 %

b) 85 %

c) 100 %

d) 125 %

e) 70 %

7) Find the difference between the total number of unmarried females in department R to that of S?

a) 156

b) 132

c) 148

d) 184

e) None of these

8) Find the average number of male employees working in department P, R and T together?

a) 748

b) 512

c) 624

d) 706

e) None of these

9) Find the ratio between the total number of married females working in department Q and S together to that of total number of employees working in P?

a) 13: 50

b) 27: 43

c) 15: 34

d) 25: 56

e) None of these

10) If the ratio of married and unmarried males in department Q is 3: 1, then find the difference between the married and unmarried males in department Q?

a) 324

b) 356

c) 272

d) 228

e) None of these

I) 8x â€“ 4y = 3x â€“ 2y + 16

8x â€“ 3x â€“ 4y + 2y = 16

5x â€“ 2y = 16 –Ã  (1)

II) 3x + 5y + 9 = 0

3x + 5y = -9 –Ã  (2)

By solving the equation (1) and (2), we get,

x = 2, y = -3

x > y

I) x2 â€“ x â€“ 72 = 0

(x â€“ 9) (x + 8) = 0

x = 9, -8

II) y2 â€“ 3y â€“ 88 = 0

(y â€“ 11) (y + 8) = 0

y = 11, -8

Canâ€™t be determined

I) 2x2 â€“ 38x + 156 = 0

2x2 â€“ 12x â€“ 26x + 156 = 0

2x (x â€“ 6) â€“ 26 (x â€“ 6) = 0

(2x â€“ 26) (x â€“ 6) = 0

x = 13, 6

II) 4y2 â€“ 34y + 66 = 0

4y2 â€“ 12y â€“ 22y + 66 = 0

4y (y â€“ 3) â€“ 22 (y â€“ 3) = 0

(4y â€“ 22) (y â€“ 3) = 0

y = 5.5, 3

x > y

I) x2 â€“ 16x â€“ 57 = 0

(x â€“ 19) (x + 3) = 0

x = 19, -3

II) y2 + 20y + 75 = 0

(y + 15) (y + 5) = 0

y = -15, -5

x > y

I) x2 = 784

x = 28, -28

II) y2 + 15y + 56 = 0

(y + 8) (y + 7) = 0

y = -8, -7

Canâ€™t be determined

Total number of female employees working in department P and S together

= > 1250*(48/100) + 1000*(44/100)

= > 600 + 440 = 1040

Total number of male employees working in department Q and T together

= > 800*(68/100) + 950*(44/100)

= > 544 + 418 = 962

Required % = (1040/962)*100 = 108 % = 110 %

The total number of unmarried females in department R

= > 650*(28/100)*(1/2) = 91

The total number of unmarried females in department S

= > 1000*(44/100)*(5/8) = 275

Required difference = 275 â€“ 91 = 184

The total number of male employees working in department P, R and T together

= > 1250*(52/100) + 650*(72/100) + 950*(44/100)

= > 650 + 468 + 418 = 1536

Required average = 1536/3 = 512

The total number of married females working in department Q and S together

= > 800*(32/100)*(5/8) + 1000*(44/100)*(3/8)

= > 160 + 165 = 325

The total number of employees working in P = 1250

Required ratio = 325: 1250 = 13: 50