Dear Readers, Bank Exam Race for theÂ Year 2018 is already started, ToÂ **enrich**Â your preparation here we have providing new series of Practice Questions onÂ Quantitative Aptitude – Section. Candidates those who are preparing forÂ **IBPS Clerk Prelims 2018** Exams can practice these questions daily and make your preparation effective.

**Click here to View Quantitative Aptitude Questions in Hindi**

**Directions (Q. 1 â€“ 5) Study the following information carefully and answer the given questions:**

The following table shows the percentage of passed girls out of the total passed students in two different colleges in 6 different years.

**1) If the total number of boys passed in the year 2012 from college P and college Q is 459 and 342 respectively, then find the total number of girls passed in the year 2012 from both the colleges together?**

a) 863

b) 949

c) 752

d) 1017

e) None of these

**2) If the total number of students passed in the year 2014 and 2016 from college P and college Q is 900 and 880 respectively, then the total number of boys passed from college P in the year 2014 is approximately what percentage of total number of girls passed from college Q in the year 2016?**

a) 128 %

b) 104 %

c) 92 %

d) 145 %

e) 73 %

**3) If the total number of students passed from college P in the year 2011 and that from college Q in the year 2013 is same, then find the ratio between the total number of boys passed from college P in the year 2011 to that of total number of girls passed from college Q in the year 2013?**

a) 15 : 19

b) 24 : 37

c) 61 : 73

d) 46 : 53

e) None of these

**4) If the total number of girls passed from college P in the year 2016 is same as total number of girls passed from college Q in the year 2015 and the total number of students passed from college Q in the year 2015 is 920, then find the total number of students passed from college P in the year 2016?**

a) 850

b) 950

c) 900

d) 800

e) None of these

**5) Find the average number of girls passed from college Q in the year 2014 and 2016 together, if the total number of students passed from college Q in the year 2014 and 2016 is 850 and 880 respectively?**

a) 412

b) 363

c) 457

d) 395

e) None of these

**Directions (Q. 6 – 10): Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.**

**6) Quantity I: **The SI on a certain sum of money for 5 years at 8 % per annum is Rs. 14000. Then the principle is?

**Quantity II: **The CI on a certain sum of money for 3 years at 5 % per annum is Rs. 6305. Then the principle is?

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**7) Quantity I: **3 years ago, the ratio of age of A and B is 3: 4. After 2 years, the sum of their ages is 45. Then find the present age of A?

**Quantity II: **5 years ago, the ratio of age of P and Q is 3: 4. Pâ€™s age after 6 years is equal to the present age of Q. Then find the present age of P?

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**8) Quantity I: **P and Q started a business by Rs. 4500 and Rs. 8000 respectively. P invested for whole year and they divided their shares after a year. The ratio of profit of P and Q is 3 : 4. Then, how many months Q invested the money?

**Quantity II: **A and B invested in the ratio of 2 : 3. A invested the money for 9 months. The ratio of profit of A and B is 3 : 4. Then, how many months B invested the money?

a) Quantity I > Quantity II

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**9) **A box contains 7 white balls, 5 violet balls and 3 yellow balls.

**Quantity I: **If 3 balls are drawn randomly, then the probability of getting at least one yellow balls?

**Quantity II: **If 2 balls are drawn randomly, then the probability of getting both the balls is either white or violet?

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**10) Quantity I: **The ratio between the downstream and upstream speed of the boat is 5: 4. The boat travels 120 km downstream in 6 hours. Find the speed of the boat in still water?

**Quantity II: **The boat travels 160 km downstream in 8 hours. The speed of the stream is 8 km/hr. Find the speed of the boat in still water?

b) Quantity I â‰¥ Quantity II

c) Quantity II > Quantity I

d) Quantity II â‰¥ Quantity I

e) Quantity I = Quantity II or Relation cannot be established

**Answers :**

**Direction (1-5) :**

**1) Answer: b)**

The total number of boys passed in the year 2012 from college P = 459

54 % of total students passed from college P in the year 2012 = 459

Total students passed from college P in the year 2012 = 459*(100/54)

Total number of girls passed in the year 2012 from college P

= > 459*(100/54)*(46/100) = 391

The total number of boys passed in the year 2012 from college Q = 342

38 % of total students passed from college Q in the year 2012 = 342

Total students passed from college Q in the year 2012 = 342*(100/38)

Total number of girls passed in the year 2012 from college Q

= > 342*(100/38)*(62/100) = 558

Required total = 391 + 558 = 949

**2) Answer: a)**

The total number of students passed in the year 2014 from college P = 900

The total number of boys passed from college P in the year 2014

= > 900*(50/100) = 450

The total number of students passed in the year 2016 from college Q = 880

The total number of girls passed from college Q in the year 2016

= > 880*(40/100) = 352

Required % = (450/352)*100 = 128 %

**3) Answer: d)**

The total number of students passed from college P in the year 2011 = The total number of students passed from college Q in the year 2013 = x

Required ratio = [x*(46/100)] : [x*(53/100)]

= > 46: 53

**4) Answer: c)**

The total number of girls passed from college P in the year 2016 = The total number of girls passed from college Q in the year 2015

The total number of students passed from college Q in the year 2015 = 920

The total number of girls passed from college Q in the year 2015

= > 920*(45/100) = 414

The total number of girls passed from college P in the year 2016 = 414

(46/100)*Total students passed from college P in the year 2016 = 414

Total students passed from college P in the year 2016 = 414*(100/46) = 900

**5) Answer: b)**

The total number of students passed from college Q in the year 2014 = 850

Total girls passed from college Q in the year 2014 = 850*(44/100) = 374

The total number of students passed from college Q in the year 2016 = 880

Total girls passed from college Q in the year 2016 = 880*(40/100) = 352

Required average = (374 + 352)/2 = 726/2 = 363

**Direction (6-10) :**

**6) Answer: c)**

**Quantity I:**

SI = (P*n*r)/100

14000 = (P*5*8)/100

P = (14000*100)/40 = Rs. 35000

**Quantity II:**

C.I = P*[(1 + (r/100))^{3} â€“ 1]

6305 = P*[(1 + 5/100)^{3} â€“ 1]

6305 = P*[(105/100)^{3} â€“ 1]

6305 = P*[(21/20)^{3} â€“ 1]

6305 = P*[(9261/8000) â€“ 1]

6305 = P*[1261/8000]

P = (6305*8000)/1261 = Rs. 40000

**Quantity I < Quantity II**

**7) Answer: c)**

**Quantity I:**

3 years ago, the ratio of age of A and B = 3: 4 (3x, 4x)

According to the question,

3x + 4x + 10 = 45

7x = 35

X = 5

The present age of A = 3x + 3 = 18 years

**Quantity II:**

5 years ago, the ratio of age of P and Q = 3: 4 (3x, 4x)

According to the question,

3x + 5 + 6 = 4x + 5

X = 6

The present age of P = 3x + 5 = 18 + 5 = 23 years

**Quantity I < Quantity II**

**8) Answer: a)**

**Quantity I:**

According to the question,

(4500*12)/(8000*x) = (3/4)

X = 9 months

**Quantity II:**

According to the question,

(2*9)/(3*x) = (3/4)

18/3x = (3/4)

72 = 9x

X = (72/9) = 8 months

**Quantity I > Quantity II**

**9) Answer: a)**

**Quantity I: **

Total probability n(S) = 15C_{3}

Required probability n(E) = 1 â€“ P(none is yellow)

Probability of getting none is yellow balls,

P(E) = n(E)/n(S) = 12C_{3}/15C_{3}

= > 44/91

Required probability = 1 â€“ (44/91) = 47/91

**Quantity II: **

Total probability n(S) = 15C_{2}

Required probability n(E) = 7C_{2} or 5C_{2}

P(E) = n(E)/n(S) = 7C_{2} or 5C_{2} / 15C_{2}

= > (21 + 10)/105 = 31/105

= > 31/105

**Quantity I > Quantity II**

**10) Answer: a)**

**Quantity I:**

Downstream speed = 120/6 = 20 km/hr

Upstream speed = 20*(4/5) = 16 km/hr

Speed of boat in still water = Â½ *(20 + 16) = 18 km/hr

**Quantity II:**

Downstream speed = 160/8 = 20 km/hr

Downstream speed = Speed of boat in still water + speed of stream

Let the speed of boat be x,

=> x + 8 = 20

=> x = 12 km/hr

Speed of boat in still water = 12 km/hr

**Quantity I > Quantity II**

**Kindly watch this video to know aboutÂ Important Table Based Data Interpretation for IBPS Clerk Prelims 2018**

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