RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-17)

Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.

[WpProQuiz 1676]

Click “Start Quiz” to attend these Questions and view Explanation

  1. The average of first thirty natural numbers is
  1. 13.5
  2. 14.5
  3. 15.5
  4. 16.5
  1. A man borrows Rs. 5,000 and pays back after 4 years at 15% simple interest. The amount paid by the man is
  1. Rs. 9,000
  2. Rs. 8,000
  3. Rs. 7,800
  4. Rs. 8,400
  1. If a @ b = a2x b2 + ab , then 3 @ 8 =
  1. 600
  2. 552
  3. 576
  4. 625
  1. Find the greatest three-digit number that is exactly divisible by 15, 25, 20 and 30.
  1. 990
  2. 900
  3. 960
  4. 930
  1. Two students Ria and Yana were paid a total amount of Rs. 840 per week by their parents. If Ria was paid 140% of the sum paid to Yana, then calculate the amount paid to Yana per week.
  1. 450
  2. 550
  3. 675
  4. 350
  1. If x = 3 and y = -1, find the value of xy + yx.
  1. 1/3
  2. – 1/3
  3. 2/3
  4. – 2/3
  1. A polygon has 35 diagonals. The number of sides in this polygon is
  1. 13
  2. 12
  3. 11
  4. 10
  1. Akash purchased 4 articles for Rs. 140 and sold 5 articles for Rs. 200. His profit percentage is
  1. 12.25%
  2. 18.80%
  3. 14.28%
  4. 24%
  1. What is the (01101)2 – (11000)2 =?
  1. 10101
  2. 11001
  3. 10111
  4. 10100
  1. The number obtained by interchanging the digits of a two-digit number is less than the original number by 18, and the sum of the digits is 6. What is the original two-digit number?
  1. 46
  2. 24
  3. 42
  4. 64

Solution:

  1. Answer: (c)

Sum of first 30 natural numbers n(n+ 1) /2 =30(30+ 1)/ 2  = 465

Therefore, average = 465/30 = 15.5

  1. Answer: (b)

S.I. = 5000x15x4/100 = Rs. 3,000

Amount = 5000 + 3000 = Rs. 8,000

  1. Answer: (a)

3 @ 8 = 32 x  82+ (3 x8) = 9 x64 + 24 = 576 + 24 = 600

  1. Answer: (b)

Greatest 3-digit number = 999

LCM of 15, 20, 25 and 30 = 300

On dividing 999 by 300, remainder = 99

Hence, the required number = 999 – 99 = 900

  1. Answer: (d)

Consider the amount paid to Yana = x. A

mount paid to Ria = 140% of x = 1.4x

Now, x + 1.4x = 840

2.4x = 840

x = 350

  1. Answer: (d)

  1. Answer: (d)

Number of diagonals in a polygon of n sides = n( n- 3) /2

n( n- 3) /2 = 35

n2 – 3n – 70 = 0

(n + 7)(n – 10) = 0

n = 10

  1. Answer: (c)

LCM of 4 and 5 = 20 Now, C.P. of 4 articles = Rs. 140

C.P. of 20 articles = 140 × 5 = Rs. 700

S.P. of 5 articles = Rs. 200

S.P. of 20 articles = 200 × 4 = 800

Profit = 800 – 700 = 100

Profit percentage = 100/700*100  = 14.28%

  1. Answer: (a)

Use 1’s complement method Calculation:

1’s compliment of 11000 = 00111

Finding the difference

01101

00111

——–

10100

1

———-

10101

———–

Hence, the value is 10101.

  1. Answer: (c)

Let the required two-digit number be xy, i.e. 10x + y.

The number obtained by interchanging the digits is 10y + x.

According to the question, 10x + y – 10y – x

9x – 9y = 18

x – y = 2

x + y = 6 (Given)

On solving these equations, we get:

x = 4 and y = 2

So, the required number = 42

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