Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.
[WpProQuiz 1676]Click “Start Quiz” to attend these Questions and view Explanation
- The average of first thirty natural numbers is
- 13.5
- 14.5
- 15.5
- 16.5
- A man borrows Rs. 5,000 and pays back after 4 years at 15% simple interest. The amount paid by the man is
- Rs. 9,000
- Rs. 8,000
- Rs. 7,800
- Rs. 8,400
- If a @ b = a2x b2 + ab , then 3 @ 8 =
- 600
- 552
- 576
- 625
- Find the greatest three-digit number that is exactly divisible by 15, 25, 20 and 30.
- 990
- 900
- 960
- 930
- Two students Ria and Yana were paid a total amount of Rs. 840 per week by their parents. If Ria was paid 140% of the sum paid to Yana, then calculate the amount paid to Yana per week.
- 450
- 550
- 675
- 350
- If x = 3 and y = -1, find the value of xy + yx.
- 1/3
- – 1/3
- 2/3
- – 2/3
- A polygon has 35 diagonals. The number of sides in this polygon is
- 13
- 12
- 11
- 10
- Akash purchased 4 articles for Rs. 140 and sold 5 articles for Rs. 200. His profit percentage is
- 12.25%
- 18.80%
- 14.28%
- 24%
- What is the (01101)2 – (11000)2 =?
- 10101
- 11001
- 10111
- 10100
- The number obtained by interchanging the digits of a two-digit number is less than the original number by 18, and the sum of the digits is 6. What is the original two-digit number?
- 46
- 24
- 42
- 64
Solution:
- Answer: (c)
Sum of first 30 natural numbers n(n+ 1) /2 =30(30+ 1)/ 2 = 465
Therefore, average = 465/30 = 15.5
- Answer: (b)
S.I. = 5000x15x4/100 = Rs. 3,000
Amount = 5000 + 3000 = Rs. 8,000
- Answer: (a)
3 @ 8 = 32 x 82+ (3 x8) = 9 x64 + 24 = 576 + 24 = 600
- Answer: (b)
Greatest 3-digit number = 999
LCM of 15, 20, 25 and 30 = 300
On dividing 999 by 300, remainder = 99
Hence, the required number = 999 – 99 = 900
- Answer: (d)
Consider the amount paid to Yana = x. A
mount paid to Ria = 140% of x = 1.4x
Now, x + 1.4x = 840
2.4x = 840
x = 350
- Answer: (d)
- Answer: (d)
Number of diagonals in a polygon of n sides = n( n- 3) /2
n( n- 3) /2 = 35
n2 – 3n – 70 = 0
(n + 7)(n – 10) = 0
n = 10
- Answer: (c)
LCM of 4 and 5 = 20 Now, C.P. of 4 articles = Rs. 140
C.P. of 20 articles = 140 × 5 = Rs. 700
S.P. of 5 articles = Rs. 200
S.P. of 20 articles = 200 × 4 = 800
Profit = 800 – 700 = 100
Profit percentage = 100/700*100 = 14.28%
- Answer: (a)
Use 1’s complement method Calculation:
1’s compliment of 11000 = 00111
Finding the difference
01101
00111
——–
10100
1
———-
10101
———–
Hence, the value is 10101.
- Answer: (c)
Let the required two-digit number be xy, i.e. 10x + y.
The number obtained by interchanging the digits is 10y + x.
According to the question, 10x + y – 10y – x
9x – 9y = 18
x – y = 2
x + y = 6 (Given)
On solving these equations, we get:
x = 4 and y = 2
So, the required number = 42
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-1)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-2)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-3)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-4)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-5)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-6)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-7)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-8)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-9)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-10)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-11)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-12)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-13)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-14)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-15)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-16)
