Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.
[WpProQuiz 2671]
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- If cot 45° + tan 60° = x, the value of x?
- 1
- √3
- 1+√3
- 0
- Simplify
500 – 25% of 400 – (13)2 =?
- 230
- 231
- 232
- 234
- The average marks scored by 50 boys were 80. Then a mark 98 was misread as 89. What is the correct mean of marks?
- 79.82
- 80.80
- 80.18
- 79. 80
- A’s is income is 25% less than B’s Income and 50% greater than C’s income. What is the ratio of income of A, B & C?
- 1: 2: 3
- 2: 4: 6
- 1:3: 6
- 6: 8: 3
5.Mohan bought a car with the discount of 20% of cost price and sold this car by earning a profit of 20% on original price of the car. Find the total loss or gain percentage of this transaction?
- 100 % gain
- 50 % gain
- Neither loss nor gain
- Cannot be determined
- The difference between compound and simple interest on a sum of money for 2 years at 6% per annum is Rs. 126. The sum is
- 40,000
- 35,000
- 30,000
- 45,000
- Side of a Square is equal to diameter of a circle. Area of a square is 49cm. Fine the Circumference of Circle?
- 44
- 11
- 22
- 33
- The point of intersection of all the perpendicular bisectors of the sides of a triangle is called
- Altitudes
- Incentre Triangle
- Circumcentre Triangle
- Medians
- When a number is divided by 455 the remainder is 42. If that number is divided by 13, theremainder will be
- 2
- 3
- 4
- 5
- Two Bikes travels From Place A to Place B with the Speed of 20 Kmph and 30 kmph respectively. One bike reached Place B 1 hour before the other bike. Find the distance between Place A and B?
- 30 Km
- 60 Km
- 120 Km
- 80 Km
Answers:
1.Answer: C
cot 45° + tan 60° = x
x = 1 + √3
2.Answer: B
500 – 100 – 169=500 – 269 = 231
3.Answer: C
Difference of Marks Misread and correct mark = 98 – 89 = 9
Average of the marks difference = 9/50 = 0.18
Total average marks = 80 + 0.18 = 80.18
4.Answer: D
A B C
150 200 75
A: B: C: = 6: 8: 3
5.Answer: B
If Cost price of Car = Rs. 100
Mohan bought this car after discount = Rs. 80
Selling price of the car= Rs.120
Profit/loss % = (S.P – C.P)* 100 = (40/80)*100 = 50%
6.Answer: B
S.I = PNR/100
S.I = (P*2*6)/100
Amt = P(1 + r/100)2
= P (1 + 6/100)2
= P (106/100)2
CI= P(53/50)2 –P
P(53/50)2 –P–(12P/100) = 126
Solve this equation, we get
P = 35,000
7.Answer: c
Let r be the radius of the circle.
Side of square = 2r
A= 49
Side = 7
2r = 7
r = 3.5
Circumference of Circle = 2πr
= 2 *22/7*3.5 = 22
8.Answer: C
The perpendicular bisectors of the sides of a triangle intersect at a point called the circumcenter of the triangle, which is equidistant from the vertices of the triangle.
9.Answer: b
Let x be the number and y be the quotient. Then,
x = 455× y + 42 = (13 x 35 × y) + (13 x 2) + 3
= 13 x (35y + 2) + 3)
∴ required remainder = 3.
10.Answer: b
Distance = Speed × Time
Given:
Speed = 20 kmph , 30 kmph
Time = 1 hour
Distance = x
(x/20) – (x/30) = 1
10 x =600
X =60 Km
RRB ALP 2018 – “All in One” Study Materials and Practice Sets
