# RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-51)

Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.

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1. If cot 45° + tan 60° = x, the value of x?
1. 1
2. √3
3. 1+√3
4. 0
1. Simplify

500 – 25% of 400  – (13)2 =?

1. 230
2. 231
3. 232
4. 234
1. The average marks scored by 50 boys were 80. Then a mark 98 was misread as 89. What is the correct mean of marks?
1. 79.82
2. 80.80
3. 80.18
4. 79. 80
1. A’s is income is 25% less than B’s Income and 50% greater than C’s income. What is the ratio of income of A, B & C?
1. 1: 2: 3
2. 2: 4: 6
3. 1:3: 6
4. 6: 8: 3

5.Mohan bought a car with the discount of 20% of cost price and sold this car by earning a profit of 20% on original price of the car. Find the total loss or gain percentage of this transaction?

1. 100 % gain
2. 50 % gain
3. Neither loss nor gain
4. Cannot be determined
1. The difference between compound and simple interest on a sum of money for 2 years at 6% per annum is Rs. 126. The sum is
1. 40,000
2. 35,000
3. 30,000
4. 45,000
1. Side of a Square is equal to diameter of a circle. Area of a square is 49cm. Fine the Circumference of Circle?
1. 44
2. 11
3. 22
4. 33
1. The point of intersection of all the perpendicular bisectors of the sides of a triangle is called
1. Altitudes
2. Incentre Triangle
3. Circumcentre Triangle
4. Medians
1. When a number is divided by 455 the remainder is 42. If that number is divided by 13, theremainder will be
1. 2
2. 3
3. 4
4. 5
1. Two Bikes travels From Place A to Place B with the Speed of 20 Kmph and 30 kmph respectively. One bike reached Place B 1 hour before the other bike. Find the distance between Place A and B?
1. 30 Km
2. 60 Km
3. 120 Km
4. 80 Km

cot 45° + tan 60° = x

x = 1 + √3

500 – 100 – 169=500 – 269 = 231

Difference of Marks Misread and correct mark = 98 – 89 = 9

Average of the marks difference = 9/50 = 0.18

Total average marks = 80 + 0.18 = 80.18

A             B             C

150        200        75

A: B: C: = 6: 8: 3

If Cost price of Car = Rs. 100

Mohan bought this car after discount = Rs. 80

Selling price of the car= Rs.120

Profit/loss % = (S.P – C.P)* 100 = (40/80)*100 = 50%

S.I = PNR/100

S.I = (P*2*6)/100

Amt =  P(1 + r/100)2

= P (1 + 6/100)2

= P (106/100)2

CI= P(53/50)2 –P

P(53/50)2 –P–(12P/100) = 126

Solve this equation, we get

P = 35,000

Let r be the radius of the circle.

Side of square = 2r

A= 49

Side = 7

2r = 7

r = 3.5

Circumference of Circle = 2πr

= 2 *22/7*3.5 = 22

The perpendicular bisectors of the sides of a triangle intersect at a point called the circumcenter of the triangle, which is equidistant from the vertices of the triangle.

Let x be the number and y be the quotient. Then,

x = 455× y + 42 = (13 x 35 × y) + (13 x 2) + 3

= 13 x (35y + 2) + 3)

∴ required remainder = 3.

Distance = Speed × Time

Given:

Speed = 20 kmph , 30 kmph

Time = 1 hour

Distance = x

(x/20) – (x/30) = 1

10 x =600

X =60 Km

RRB ALP 2018 – “All in One” Study Materials and Practice Sets 