Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for **SBI Clerk Mains 2020 **so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

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**Data Interpretation**

**Directions (1 – 5): Study the following information carefully and answer the given questions?**

The pie chart shows the total employees working in different departments in a company and the line graph shows the percentage of graduate employees among them.

** **

**1) Find the difference between the total number of graduate employees in company A to that of total number of non graduate employees in company D?**

a) 340

b) 260

c) 420

d) 580

e) None of these

**2) Find the average number of graduate employees in company A, B and C together?**

a) 2800

b) 1950

c) 3100

d) 2550

e) None of these

**3) Find the ratio between the total employees in company C to that of total non graduate employees in company E and F together?**

a) 81: 82

b) 53: 57

c) 11: 13

d) 75: 79

e) None of these

**4) Total employees in company D and F together is what percentage of total non graduate employees in company A and B together?**

a) 250 %

b) 425 %

c) 375 %

d) 180 %

e) None of these

**5) Find the difference between the average employees in company D, E and F together to that of total non graduate employees in company B, C and F together?**

a) 850

b) 740

c) 930

d) 1020

e) None of these

**Quantity based questions**

**Directions (6 – 10): ****Each question contains a statement followed by Quantity I, quantity II and Quantity III. ****Which of the following should be placed in the blank spaces of the expression “Quantity I __ Quantity II ___ Quantity III” from left to right with respect to the given statements?**

**6) Quantity I: **(840 – 384) ÷ 24 + 787 =?

**Quantity II: **45 % of 600 – 18 % of 350 =? – 62 – 25^{2}

**Quantity III: **? = (3745 + 1780) ÷ 17 + 16^{2} + (5/11) of 880 – 15

a) >, <

b) >, >

c) <, <

d) =, >

e) None of these

**7) Quantity I: **38 % of 350 + 400 % of 16 =? % of 50

**Quantity II:** 156 ÷ 13 + ∛19683 – (12 × 15) =? – 8^{3}

**Quantity III:** (√2500)^{3} =?

a) >, =

b) >, <

c) =, <

d) =, =

e) None of these

**8) Quantity I: **x^{2} – 17x + 72 = 0

**Quantity II: **y^{2} -19y + 88 = 0

**Quantity III: **3x^{2 }+ 26x + 56 = 0

a) >, =

b) ≥, =

c) ≤, ≤

d) <, <

e) None of these

**9) Quantity I: **578, 600, 630, 669, 718, ?

**Quantity II: **8, 9, 14, 51, 188, ? , 5754

**Quantity III: **56, 114, ? , 1384, 6925, 41556

a) <, <

b) >, >

c) =, >

d) <, >

e) None of these

**10) A contains 4 pink, 6 red and 5 blue colour balls. **

**Quantity I: **Two balls are taken randomly from the bag; find the probability of getting both is blue?

**Quantity II: **Two balls are taken randomly from the bag, find the probability of getting at least one pink ball

**Quantity III: **Two balls are taken randomly from the bag; find the probability of getting one red and one pink

a) <, >

b) >, >

c) <, <

d) =, =

e) None of these

**Answers :**

**Directions (1-5) :**

**1) Answer: B**

The total number of graduate employees in company A

= > 5000 * (12/100) = 600

The total number of non graduate employees in company D

= > [9000 * (24/100)] – [5000 * (26/100)]

= > 2160 – 1300 = 860

Required difference = 860 – 600 = 260

**2) Answer: D**

The average number of graduate employees in company A, B and C together

= > 5000 * (51/100) = 2550

**3) Answer: A**

The total employees in company C

= > 9000 * (18/100) = 1620

The total non graduate employees in company E and F together

= > {[9000 * (10/100) – 5000 * (8/100)] + [(9000 * (21/100) – 5000 * (15/100)]}

= > {[900 – 400] + [1890 – 750]}

= > 500 + 1140 = 1640

Required ratio = 1620: 1640 = 81: 82

**4) Answer: C**

Total employees in company D and F together

= > 9000 * (45/100) = 4050

Total non graduate employees in company A and B together

= > {[9000 * (15/100) – 5000 * (12/100)] + [9000 * (12/100) – 5000 * (15/100)]}

= > {[1350 – 600] + [1080 – 750]}

= > 750 + 330 = 1080

Required % = (4050 / 1080) * 100 = 375 %

**5) Answer: D**

The average employees in company D, E and F together

= > 9000 * (55/100) * (1/3) = 1650

The total non graduate employees in company B, C and F together

= > {[9000 * (12/100) – 5000 * (15/100)] + [9000 * (18/100) – 5000 * (24/100)] + [9000 * (21/100) – 5000 * (15/100)]} * (1/3)

= > {[1080 – 750] + [1620 – 1200] + [1890 – 1140]} * (1/3)

= > (330 + 420 + 1140) / 3 = 1890 / 3

= > 630

Required difference = 1650 – 630 = 1020

**Directions (6-10) :**

**6) Answer: C**

**Quantity I: **

(840 – 384) / 24 + 787 = x

x = 456 / 24 + 787

x = 20 + 787 = 807 = 810

**Quantity II: **

45 % of 600 – 18 % of 350 = x – 62 – 25^{2}

(45/100) * 600 – (18/100) * 350 + 62 + 625 = x

x = 270 – 63 + 62 + 625

x = 894

**Quantity III: **

x = (3745 + 1780) ÷ 17 + 16^{2} + (5/11) of 880 – 15

x = 5525/17 + 256 + (5/11) * 880 – 15

x = 325 + 256 + 400 – 15

x = 966

**Hence, Quantity I < Quantity II < Quantity III**

**7) Answer: B**

**Quantity I: **

38 % of 350 + 400 % of 16 = x % of 50

(38/100) * 350 + (400/100)*16 = (x/100) * 50

133 + 64 = x/2

197*2 = x

x = 394

**Quantity II: **

156 ÷ 13 + ∛19683 – (12 × 15) = x – 8^{3}

(156/13) + 27 – (12*15) + 512 = x

x = 12 + 27 – 180 + 512

x = 371

**Quantity III: **

(√2500)^{3 }=?

(50)^{3} =?

125000 =?

**Hence, Quantity I > Quantity II < Quantity III**

**8) Answer: E**

**Quantity I: **

x^{2} – 17x + 72 = 0

(x – 8) (x – 9) = 0

x = 8, 9

**Quantity II: **

y^{2} -20y + 99 = 0

(y – 11) (y – 9) = 0

y = 11, 9

**Quantity III: **

3x^{2 }+ 26x + 56 = 0

3x^{2 }+ 12x + 14x + 56 = 0

3x(x + 4) + 14(x + 4) = 0

(3x + 14) (x + 4) = 0

x = -14/3, -4 = -4.667, -4

**Hence, Quantity I ≤ Quantity II > Quantity III**

**9) Answer: D**

**Quantity I:**

The difference of difference is, 8, 9, 10, 11,..

The answer is, 778

**Quantity II: **

The pattern is, * 1 + 1^{2}, * 2 – 2^{2}, * 3 + 3^{2}, * 4 – 4^{2}, * 5 + 5^{2}, * 6 – 6^{2},…

The answer is, 965

**Quantity III: **

The pattern is, * 2 + 2, * 3 + 3, * 4 + 4, * 5 + 5, * 6 + 6,…

The answer is, 345

**Hence, Quantity I < Quantity II > Quantity III**

**10) Answer: A**

**Quantity I: **

Required probability = 5C_{2}/15C_{2}

= (5 * 4)/(15 * 14)

= 2/21 = 0.095

**Quantity II: **

Required probability = 1 – (None pink)

= 1 – 11C_{2}/15C_{2}

= 1 – [(11 * 10)/(15 * 14)]

= 1 – 11/21 = 10/21 = 0.476

**Quantity III: **Two balls are taken randomly from the bag; find the probability of getting one red and one pink

Required probability = (6C_{1} * 4C_{1})/15C_{2}

= (6 * 4)/(15 * 14)

= 4/35 = 0.114

**Hence, Quantity I < Quantity II > Quantity III**

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