# SBI Clerk Prelims 2021 Quantitative Aptitude Questions (Day-42)

Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Prelims 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

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Directions (01-05): Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

1) I)Â
x2Â + 13x + 22 = 0

II)y2+ 15y + 26 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship cannot be determined.

D.x < y

E.x â‰¤ y

2) I)Â
5x2Â – 15x + 10 = 0

II)y2– 5y + 6 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship cannot be determined.

D.x < y

E.x â‰¤ y

3) I)Â
x2Â â€“ 12x + 32 = 0

II)y2â€“ 17y + 72 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship cannot be determined.

D.x < y

E.x â‰¤ y

4) I)
Â x2Â â€“ 32x + 252 = 0

II)y2â€“ 26y + 168 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship cannot be determined.

D.x < y

E.x â‰¤ y

5) I)
Â x2Â + 13x + 40 = 0

II)y2+ 19y + 90 = 0

A.x > y

B.x â‰¥ y

C.x = y or relationship cannot be determined.

D.x < y

E.x â‰¤ y

Approximation

Directions (06-10): What approximate value should come in the place of (?) in the following questions?

6) 8.11 * âˆš1295 + 18.95 * 23.01 – âˆš120 * 47.91 =?

A.191

B.197

C.213

D.220

E.228

7) 7.981 % of 325 + 30.891 % of 699.871 + 127.01 =?

A.340

B.370

C.390

D.410

E.430

8) 150.03% of 185.781 – 21.11 % of 899.91 =?

A.70

B.90

C.80

D.60

E.50

9) 33.06 * âˆš7055 â€“ âˆš2210 * âˆš3135 =? * âˆš50

A.10

B.15

C.20

D.25

E.30

10) âˆš4760 – âˆš3250 + âˆš6560 =?

A.79

B.54

C.65

D.93

E.89

x2Â + 13x + 22 = 0

x2Â + 11x + 2x + 22 = 0

x(x + 11) + 2(x + 11) = 0

(x + 2)(x + 11) = 0

x = -2, -11

y2Â + 15y + 26 = 0

y2Â + 13y + 2y + 26 = 0

y(y + 13) + 2(y + 13) = 0

(y + 2)(y + 13) = 0

y = -2, -13

Relationship between x and y cannot be established.

5x2Â – 15x + 10 = 0

5x2Â â€“ 10x â€“ 5x + 10 = 0

5x(x â€“ 2) â€“ 5(x â€“ 2) = 0

(5x â€“ 5)(x â€“ 2) = 0

x = 1, 2

y2Â – 5y + 6 = 0

y2Â â€“ 2y â€“ 3y + 6 = 0

y(y â€“ 2) â€“ 3(y â€“ 2) = 0

(y â€“ 3)(y â€“ 2) = 0

y = 3, 2

x â‰¤ y

x2Â â€“ 12x + 32 = 0

x2Â â€“ 8x â€“ 4x + 32 = 0

x(x â€“ 8) â€“ 4(x â€“ 8) = 0

(x â€“ 4)(x â€“ 8) = 0

x = 4, 8

y2Â â€“ 17y + 72 = 0

y2Â â€“ 8y â€“ 9y + 72 = 0

y(y â€“ 8) â€“ 9(y â€“ 8) = 0

(y â€“ 9)(y â€“ 8) = 0

y = 9, 8

x â‰¤ y

x2Â â€“ 32x + 252 = 0

x2Â â€“ 14x â€“ 18x + 252 = 0

x(x â€“ 14) â€“ 18(x â€“ 14) = 0

(x â€“ 18)(x â€“ 14) = 0

x = 18, 14

y2Â â€“ 26y + 168 = 0

y2Â â€“ 14y â€“ 12y + 168 = 0

y(y â€“ 14) â€“ 12(y â€“ 14) = 0

(y â€“ 12)(y â€“ 14) = 0

y = 12, 14

x â‰¥ y

x2Â + 13x + 40 = 0

x2Â + 8x + 5x + 40 = 0

x(x + 8) + 5(x + 8) = 0

(x + 5)(x + 8) = 0

x = -5, -8

y2Â + 19y + 90 = 0

y2Â + 9y + 10y + 90 = 0

y(y + 9) + 10(y + 9) = 0

(y + 10)(y + 9) = 0

y = -10, -9

x > y

8.11 * âˆš1295 + 18.95 * 23.01 – âˆš120 * 47.91 =?

8 * âˆš1296 + 19 * 23 – âˆš121 * 48 =?

288 + 437 – 528 =?

? = 197

7.981 % of 325 + 30.891 % of 699.871 + 127.01 =?

8/100 * 325 + 31/100 * 700 + 127 =?

26 + 217 + 127 =?

370 =?

150.03% of 185.781 – 21.11 % of 899.91 =?

150/100 * 186 â€“ 21/100 * 900 =?

279 â€“ 189 =?

90 =?

33.06 * âˆš7055 â€“ âˆš2210 * âˆš3135 =? * âˆš50

33 * âˆš7056 – âˆš2209 * âˆš3136 =? * âˆš49

33 * 84 â€“ 47 * 56 =? * 7

2772 â€“ 2632 =? * 7

? = 20

âˆš4760 – âˆš3250 + âˆš6560 =?

âˆš4761 – âˆš3249 + âˆš6561 =?

69 â€“ 57 + 81 =?

? = 93

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