[Dated: 26th April] Practice Quantitative Aptitude Questions For SBI PO Prelims 2017 (Number Series):
Dear Readers, Important Practice Aptitude Questions for Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this.
Directions (Q. 1-10): Find out the missing number in place of question mark (?) in the following number series.
1). 3, 7, 29, 143, 779, ?
a) 4997
b) 4649
c) 4847
d) 4799
e) 4999
2). 4, 5, ?, 88, 620, 5585
a) 16
b) 18
c) 17
d) 20
e) 22
3). 11, 20, 42, ?, 166, 330
a) 72
b) 66
c) 86
d) 80
e) 82
4). 128, 64, 96, 240, ?, 3780
a) 740
b) 840
c) 850
d) 845
e) 745
5). 8484, ?, 8486, 8495, 8488, 8493
a) 8485
b) 8584
c) 8684
d) 8497
e) 8496
6). 68, 132, 268, ?, 1068, 2132
a) 394
b) 464
c) 325
d) 532
e) 484
7). 23, 12, 13, 21, ?, 112.5
a) 33
b) 44
c) 55
d) 66
e) 65
8). 8, 10, 18, 44, 124, ?
a) 366
b) 263
c) 194
d) 276
e) 286
9). 4, 4, 21, 68, ?, 2154
a) 435
b) 365
c) 462
d) 572
e) 425
10). 7, 20, 59, 176, ?, 1580
a) 527
b) 526
c) 627
d) 562
e) 270
Explanation:
1). D)
The series is x2 + 13, x3 + 23, x4 + 33, x5 + 43, …
ie 3 x 2 +13 = 7,
7 x 3 + 23 = 29,
29 x 4 + 33 = 143,
143 x 5 +43 = 779,
779 x 6 + 53= 4799,
2). C)
The series is x1 + 1, x3 + 2, ×5 + 3, x7 + 4, x9 + 5, x11 + 6,
Ie 4 x 1+1 = 5,
5 x3+2=17,
17 x 5 + 3 = 88,
88 x 7 + 4 = 620,
620 x 9 + 5 = 5585,
3). E)
The series is x2 – 2, x2 + 2, (Alternately repeated)
4). B)
The series is x0.5, x1.5, x2.5, x3.5, …
5). D)
The series is +13, —11, +9, —7, +5, … +13
6). D)
The series is x2 – 4, x2 + 4, (repeated)
7). B)
The series is ×1/2 + 0.5, ×1+1, ×1.5+1.5…..
8). A)
The series is
9). B)
The Series is
10). A)
The series is ×3 – 1, ×3 – 1 (repeated)
7 × 3 = 21 – 1 = 20
20 × 3 = 60 – 1 = 59
59 × 3 = 177 – 1 = 176
176 × 3 = 528 – 1 = 527
527 × 3 = 1581 – 1 = 1580
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