RRB PO Prelims Quantitative Aptitude (Day-04)

Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for RRB PO 2020 Prelims so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

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Direction (1-5): What should come in the place of question mark in the following number series?Â

1) 3, 10, 32, 111, 460, ?

A) 2215

B) 2320

C) 2310

D) 2314

E) 2315

2) 40, 48, 60, 78,Â  ? , 147.42

A) 105.5

B) 106.5

C) 105.3

D) 106.3

E) 112.3

3) 16, 19, 24, 33, 50, ?

A) 83

B) 99

C) 66

D) 77

E) 102

4) 58, 128, 260, 442, 714, ?

A) 1129

B) 1135

C) 1056

D) 1133

E) 1115

5) Â 999, 1647, 2457, 3429, 4563, ?

A) 5868

B) 5879

C) 5869

D) 5881

E) 5859

Direction (6-10): Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them

6)

A) X > Y

B) X â‰¤ Y

C) Relationship between X and Y canâ€™t be established

D) X â‰¥ Y

E) X < Y

7)

I) 7X2– 35âˆš3X+126Â = 0

II) 9Y2Â – 27âˆš3Y-270= 0

A) X > Y

B) X â‰¤ Y

C) Relationship between X and Y canâ€™t be established

D) X â‰¥ Y

E) X < Y

8)

A) X > Y

B) X â‰¤ Y

C) Relationship between X and Y canâ€™t be established

D) X â‰¥ Y

E) X < Y

9)

I) 55X2Â – 32X – 63 = 0

II) 33Y2â€“ 49Y + 18 = 0

A) X > Y

B) X â‰¤ Y

C) Relationship between X and Y canâ€™t be established

D) X â‰¥ Y

E) X < Y

10)

I) 2x2Â – 25x+ 75 =0

II) 4y2Â + 12y = 91

A) X > Y

B) X â‰¤ Y

C) Relationship between X and Y canâ€™t be established

D) X â‰¥ Y

E) X < Y

Directions (1-5) :

3 x 1 + (1 x 7) = 10

10 x 2 + (2 x 6) = 32

32 x 3 + (3 x 5) = 111

111 x 4 + (4 x 4) = 460

460 x 5 + (5 x 3) =Â 2315

40 x 1.2 = 48

48 x 1.25 = 60

60 x 1.3 = 78

78 x 1.35 =Â 105.3

105.3 x 1.4 = 147.42

16 + (21Â + 1) = 19

19 + (22Â + 1) = 24

24 + (23Â + 1) = 33

33 + (24Â + 1) = 50

50 + (25Â + 1) =Â 83

58 + 7 x 10 = 128

128 + 11 x 12 = 260

260 + 13 x 14 = 442

442 + 17 x 16= 714

714 + 19 x 18 =Â 1056

123Â â€“ 93Â = 999

153Â – 123Â = 1647

183Â – 153Â = 2457

213Â – 183Â = 3429

243Â – 213Â = 4563

273Â – 243Â = 5859

Directions (6-10) :

Multiply both the sides with

X2+X = 2

X2+Xâ€“ 2 = 0

X (X +2) â€“ 1(X+2) = 0

(X-1) (X+2) = 0

X = +1, -2

II. 3Y2â€“ 46Y +91= 0

3Y2Â â€“ 39Y -7Y + 91= 0

3Y (Y – 13) â€“ 7 (Y – 13) = 0

(3Y -7) (Y-13) = 0

Y = 7/3 , 13

Hence, X < Y.

I) 7X2– 35âˆš3X+126= 0

X2Â – 5âˆš3X+18 = 0

X2Â – 2âˆš3X-3âˆš3X+18 = 0

(X- 2âˆš3) (X – 3âˆš3) = 0

X = 2âˆš3, 3âˆš3

II) 9Y2Â – 27âˆš3Y-270= 0

Y2Â – 3âˆš3Y-30 = 0

Y2Â – 5âˆš3Y+2âˆš3Y-30Â = 0

(Y+2âˆš3) (Y – 5âˆš3) = 0

Y = -2âˆš3, +5âˆš3

Hence, no relation between X and Y.

2Y2Â + 6Y – 108 = 0

Y2Â + 3Y – 54 = 0

Y2Â + 9Y –Â  6Y- 54 = 0

Y (Y+9) â€“ 6 (Y+9) = 0

(Y + 9) (Y – 6) = 0

Y = +6, -9

4X2+ 23X – 117 = 0

4X2+ 36X – 13X -117 = 0

4X(X+9) – 13(X+9) = 0

(X+9) (4X -13) = 0

X = -9, 13/4

Hence, No relation between X and Y.

I) 55X2Â – 32X – 63 = 0

55X2Â – 77X +45X – 63 = 0

11X (5X – 7) + 9 (5X -7) = 0

(5X -7) (11X +9) = 0

X= 7/5, -9/11

II) 33Y2â€“ 49Y + 18 = 0

33Y2Â â€“ 22Y -27Y + 18 = 0

11Y (3Y -2) â€“ 9(3Y-2) = 0

(3Y-2) (11Y-9) = 0

Y = 2/3, 9/11

Hence, No relation between X and Y.

I) 2x2Â – 25x + 75=0

2x2Â – 10x -15x + 75 = 0

2x (x – 5) â€“ 15 (x – 5) = 0

(x -5) (2x – 15) = 0

X = 15/2 ,5

II) 4y2Â + 12y = 91

4y2Â + 12y â€“ 91 = 0

4y2Â -14y +26y â€“ 91 = 0

2y (2y -7) + 13 (2y -7) = 0

(2y +13) (2y -7) = 0

Hence, X > Y.

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