RRB PO Prelims Quantitative Aptitude (Day-04)

Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for RRB PO 2020 Prelims so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

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Direction (1-5): What should come in the place of question mark in the following number series? 

1) 3, 10, 32, 111, 460, ?

A) 2215

B) 2320

C) 2310

D) 2314

E) 2315

2) 40, 48, 60, 78,  ? , 147.42

A) 105.5

B) 106.5

C) 105.3

D) 106.3

E) 112.3

3) 16, 19, 24, 33, 50, ?

A) 83

B) 99

C) 66

D) 77

E) 102

4) 58, 128, 260, 442, 714, ?

A) 1129

B) 1135

C) 1056

D) 1133

E) 1115

5)  999, 1647, 2457, 3429, 4563, ?

A) 5868

B) 5879

C) 5869

D) 5881

E) 5859

Quadratic Equation

Direction (6-10): Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them

6)

A) X > Y

B) X ≤ Y

C) Relationship between X and Y can’t be established

D) X ≥ Y

E) X < Y

7)

I) 7X²– 35√3X+126 = 0

II) 9Y² – 27√3Y-270= 0

A) X > Y

B) X ≤ Y

C) Relationship between X and Y can’t be established

D) X ≥ Y

E) X < Y

8)

A) X > Y

B) X ≤ Y

C) Relationship between X and Y can’t be established

D) X ≥ Y

E) X < Y

9)

I) 55X² – 32X – 63 = 0

II) 33Y²– 49Y + 18 = 0

A) X > Y

B) X ≤ Y

C) Relationship between X and Y can’t be established

D) X ≥ Y

E) X < Y

10)

I) 2x² – 25x+ 75 =0

II) 4y² + 12y = 91

A) X > Y

B) X ≤ Y

C) Relationship between X and Y can’t be established

D) X ≥ Y

E) X < Y

Answers :

Directions (1-5) :

1) Answer: E

3 x 1 + (1 x 7) = 10

10 x 2 + (2 x 6) = 32

32 x 3 + (3 x 5) = 111

111 x 4 + (4 x 4) = 460

460 x 5 + (5 x 3) = 2315

2) Answer: C

40 x 1.2 = 48

48 x 1.25 = 60

60 x 1.3 = 78

78 x 1.35 = 105.3

105.3 x 1.4 = 147.42

3) Answer: A

16 + (2¹ + 1) = 19

19 + (2² + 1) = 24

24 + (2³ + 1) = 33

33 + (2⁴ + 1) = 50

50 + (2⁵ + 1) = 83

4) Answer: C

58 + 7 x 10 = 128

128 + 11 x 12 = 260

260 + 13 x 14 = 442

442 + 17 x 16= 714

714 + 19 x 18 = 1056

5) Answer: E

12³ – 9³ = 999

15³ – 12³ = 1647

18³ – 15³ = 2457

21³ – 18³ = 3429

24³ – 21³ = 4563

27³ – 24³ = 5859

Directions (6-10) :

6) Answer: E

Multiply both the sides with

X²+X = 2

X²+X– 2 = 0

X (X +2) – 1(X+2) = 0

(X-1) (X+2) = 0

X = +1, -2

II. 3Y²– 46Y +91= 0

3Y² – 39Y -7Y + 91= 0

3Y (Y – 13) – 7 (Y – 13) = 0

(3Y -7) (Y-13) = 0

Y = 7/3 , 13

Hence, X < Y.

7) Answer: C

I) 7X²– 35√3X+126= 0

X² – 5√3X+18 = 0

X² – 2√3X-3√3X+18 = 0

(X- 2√3) (X – 3√3) = 0

X = 2√3, 3√3

II) 9Y² – 27√3Y-270= 0

Y² – 3√3Y-30 = 0

Y² – 5√3Y+2√3Y-30 = 0

(Y+2√3) (Y – 5√3) = 0

Y = -2√3, +5√3

Hence, no relation between X and Y.

8) Answer: C

2Y² + 6Y – 108 = 0

Y² + 3Y – 54 = 0

Y² + 9Y –  6Y- 54 = 0

Y (Y+9) – 6 (Y+9) = 0

(Y + 9) (Y – 6) = 0

Y = +6, -9

4X²+ 23X – 117 = 0

4X²+ 36X – 13X -117 = 0

4X(X+9) – 13(X+9) = 0

(X+9) (4X -13) = 0

X = -9, 13/4

Hence, No relation between X and Y.

9) Answer: C

I) 55X² – 32X – 63 = 0

55X² – 77X +45X – 63 = 0

11X (5X – 7) + 9 (5X -7) = 0

(5X -7) (11X +9) = 0

X= 7/5, -9/11

II) 33Y²– 49Y + 18 = 0

33Y² – 22Y -27Y + 18 = 0

11Y (3Y -2) – 9(3Y-2) = 0

(3Y-2) (11Y-9) = 0

Y = 2/3, 9/11

Hence, No relation between X and Y.

10) Answer: A

I) 2x² – 25x + 75=0

2x² – 10x -15x + 75 = 0

2x (x – 5) – 15 (x – 5) = 0

(x -5) (2x – 15) = 0

X = 15/2 ,5

II) 4y² + 12y = 91

4y² + 12y – 91 = 0

4y² -14y +26y – 91 = 0

2y (2y -7) + 13 (2y -7) = 0

(2y +13) (2y -7) = 0

Hence, X > Y.

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