SBI PO Prelims Quantitative Aptitude (Day-15)

Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI PO 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

Start Quiz

Ensure Your Ability Before the Exam – Take SBI PO 2020 Prelims Free Mock            Test

Application Sums

1) Three pipes A, B and C can fill a cistern in 6, 12 and 18 hours respectively. If pipe A is kept open  all  the time and pipe B and C is opened alternatively for an hour, then find in how many hour the tank will be filled?

A) 4 2/9 hours

B) 5 8/15 hours

C) 4 7/12 hours

D) 5 3/7 hours

E) None of these

2) A, B and C started a business with investment in the ratio 4: 8: 9 respectively. After 1 year, A withdrew 50 % of his capital and B increased his capital by 30% of his investment. At the end of 2 years, they earned a profit of Rs. 159000. Find the share of B in the profit?

A) Rs. 52000

B) Rs. 63000

C) Rs. 57000

D) Rs. 69000

E) None of these

3) The difference between CI and SI on a certain amount at 12 % per annum for three years is Rs. 2246.4. Find the sum?

A) Rs. 42000

B) Rs. 35000

C) Rs. 60000

D) Rs. 40000

E) None of these

4) A box contains 5 red balls, 3 white balls, 7 black balls. If two balls are drawn out randomly, then find the probability that both balls are either red or black balls?

A) 31/105

B) 17/67

C) 4/35

D) 13/89

E) None of these

5) The sum of the present ages of the four members of a family is 118 years. 2 years ago, the ages of the four members A, B, C and D were in the ratio of 4 : 5 : 6 : 7. After how many years would A be as old as the present age of D?

A) 15 years

B) 12 years

C) 18 years

D) 10 years

E) None of these

Quadratic Equation

Directions (Q. 6 – 10): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,

6)

I) x = √676 ÷ ∛2197

II) y2= 4

A) If x > y

B) If x = y or no relation can be established between x and y

C) If x < y

D) If x ≤ y

E) If x ≥ y

7)

I) 2x – 3y = -1

II)3x + 2y = -21

A) If x > y

B) If x ≥ y

C) If x < y

D) If x ≤ y

E) If x = y or no relation can be established between x and y

8)

I) x2– 4x – 21 = 0

II)y2– 8y +16 = 0

A) If x = y or no relation can be established between x and y

B) If x ≥ y

C) If x < y

D) If x ≤ y

E) If x > y

9)

I) x2+ 520 = 641

II)y = -√144

A) If x = y or no relation can be established between x and y

B) If x ≥ y

C) If x < y

D) If x ≤ y

E) If x > y

10)

I) 2x2+ 13x + 21 = 0

II)3y2+ 4y – 15 = 0

A) If x > y

B) If x ≥ y

C) If x < y

D) If x = y or no relation can be established between x and y

E) If x ≤ y

Answers :

Directions (1-5) :

1) Answer: A

Total units of work = 36 units (LCM of 6, 12 and 18)

A’s 1 hour work = 6 units

B’s 1 hour work = 3 units

C’s 1 hour work = 2 units

Work done by three pipes in 2 hours = 9 + 8 = 17 units

Work done in 4 hours = 17*2 = 34 units

Remaining will be done by pipe A= 2/9

Total time required= 4 2/9 hours

2) Answer: D

Ratio of shares:

A : B : C = (4*1 + 4*(50/100)) : (8*1 + 8*(130/100)*1) : (9*2)

= > 6 : 92/5 : 18

= > 15 : 46 : 45

The share of B in the profit = (46/106)*159000 = Rs. 69000

3) Answer: E

The difference between CI and SI for three years,

Diff = P*[(r2 * (r + 300)]/1003

= > 2246.4 = P*[122 * (12 + 300)]/1003

= > 2246.4 = P*[144*312]/(100*100*100)

= > P = [2246.4*100*100*100]/(144*312)

= > P = Rs. 50000

4) Answer: A

P(E) = n(E)/n(S)

n(S) = 15C2

n(E) = 5C2 or 7C2

P(E) = 5C2 or 7C2 / 15C2

P(E) = 31/105

5) Answer: A

According to the question,

4x + 5x + 6x + 7x + 2 * 4 = 118

= > 22x = 118 – 8

= > 22x = 110

= > x = 5

Present age of A = 4x + 2 = 22 years

Present age of D = 7x + 2 = 37 years

Required number of years = 37 – 22 = 15 years

Directions (6-10) :

6) Answer: E

I) x = √676 ÷ ∛2197

X = 26/13 = 2

II) y2= 4

y = 2, -2

X ≥ y

7) Answer: C

2x – 3y = -1 –> (1)

3x + 2y = -21 –> (2)

By solving the equation (1) and (2), we get,

X = -5, y = -3

x < y

8) Answer: A

I) x2– 4x – 21 = 0

(x – 7) (x + 3) = 0

X = 7, -3

II)y2-8y +16 = 0

(y – 4) (y – 4) = 0

Y = 4, 4

Can’t be determined

9) Answer: E

I) x2+ 520 = 641

X2 = 641 – 520 = 121

X = 11, -11

II)y = -√144

Y = -12

X > y

10) Answer: E

I) 2x2+ 13x + 21 = 0

2x2 + 6x + 7x + 21 = 0

2x (x + 3) + 7(x + 3) = 0

(2x + 7) (x + 3) = 0

X = -7/2, -3 = -3.5, -3

II)3y2+ 4y – 15 = 0

3y2 + 9y – 5y – 15 = 0

3y (y + 3) -5(y + 3) = 0

(3y – 5) (y + 3) = 0

Y = 5/3, -3 = 1.667, -3

X ≤ y

Check Here to View SBI PO Prelims 2020 Quantitative Aptitude Questions
Day – 14 Day – 13 Day – 12
Click Here for SBI Clerk 2020 – Detailed Exam Notification

0 0 votes
Rating
Subscribe
Notify of
guest
0 Comments
Inline Feedbacks
View all comments