RRB PO Prelims Quantitative Aptitude (Day-14)

Quantitative Aptitude for RRB PO 2020

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IBPS RRB PO Prelims

Data Interpretation

Direction (1-5): Study the following information carefully and answer the given questions.

The following table shows the total number of people bought books from 6 different stores in May 2019 and the ratio of male and female among them.

1) Find the difference between the total number of males bought books from store A and B together to that of total number of females bought books from store E and F together?

A) 108

B) 115

C) 136

D) 127

E) None of these

2) Find the ratio between the total number of people bought books from store C to that of total number of females bought books from store D?

A) 47: 55

B) 60: 49

C) 52: 43

D) 75: 67

E) None of these

3) Total number of males bought books from store A and F together is approximately what percentage of total number of females bought books from store B?

A) 223 %

B) 192 %

C) 256 %

D) 177 %

E) 165 %

4) Find the total number of females bought books from store B, C, D and E together?

A) 844

B) 916

C) 872

D) 998

E) None of these

5) If the percentage of horror books bought from store B and C is 45 % and 60 % respectively, then find the total number of story books bought from store B and C together (The available books from all the stores are Horror and Story books only)?

A) 420

B) 390

C) 360

D) 440

E) None of these

Quadratic Equation

Direction (6-10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

6)

I) 2x²– 3x – 44 = 0

II) 3y²– 20y + 25 = 0

7)

I) 3x – 2y = 2

II) 5x – 4y = 0 

8)

I) x²+ 7x – 78 = 0

II) y²+ 27y + 182 = 0 

9)

I) 2x²– 10x – 48 = 0

II) y²+ 9y + 20 = 0

10)

I) x = ∜65536 % of 450 – 12²+ 80

II) y³= 1728

Answers :

Directions (1-5):

1) Answer: A

The total number of males bought books from store A and B together

= > 2400 * (18/100) * (5/8) + 2400 * (15/100) * (4/9)

= > 270 + 160 = 430

The total number of females bought books from store E and F together

= > 2400 * (14/100) * (5/8) + 2400 * (12/100) * (7/18)

= > 210 + 112 = 322

Required difference = 430 – 322 = 108

2) Answer: B

The total number of people bought books from store C

= > 2400 * (20/100)

The total number of females bought books from store D

= > 2400 * (21/100) * (7/9)

Required ratio = [2400 * (20/100)]: [2400 * (21/100) * (7/9)]

= > 60: 49

3) Answer: A

Total number of males bought books from store A and F together

= > 2400 * (18/100) * (5/8) + 2400 * (12/100) * (11/18)

= > 270 + 176 = 446

Total number of females bought books from store B

= > 2400 * (15/100) * (5/9) = 200

Required % = (446/200) * 100 = 223 %

4) Answer: E

The total number of females bought books from store B, C, D and E together

= > [2400 * (15/100) * (5/9) + 2400 * (20/100) * (1/3) + 2400 * (21/100) * (7/9) + 2400 * (14/100) * (5/8)]

= > (200 + 160 + 392 + 210)

= > 962

5) Answer: B

The total number of story books bought from store B and C together

= > 2400 * (15/100) * (55/100) + 2400 * (20/100) * (40/100)

= > 198 + 192 = 390

Directions (6-10) :

6) Answer: E

I) 2x²– 3x – 44 = 0

2x² + 8x – 11x – 44 = 0

2x (x + 4) – 11 (x + 4) = 0

(2x – 11) (x + 4) = 0

x = 11/2, -4 = 5.5, -4

II) 3y²– 20y + 25 = 0

3y² – 15y – 5y + 25 = 0

3y (y – 5) – 5 (y – 5) = 0

(3y – 5) (y – 5) = 0

y = 5/3, 5 = 1.66, 5

Can’t be determined

7) Answer: C

3x – 2y = 2 –> (1)

5x – 4y = 0 –> (2)

By solving the equation (1) and (2), we get,

x = 4, y = 5

x < y

8) Answer: B

I) x²+ 7x – 78 = 0

(x + 13) (x – 6) = 0

x = -13, 6

II)y²+ 27y + 182 = 0

(y + 14) (y + 13) = 0

y = – 14, -13

x ≥ y

9) Answer: A

I) 2x²– 10x – 48 = 0

2x² – 16x + 6x – 48 = 0

2x (x – 8) + 6 (x – 8) = 0

(2x + 6) (x – 8) = 0

x = -3, 8

II) y²+ 9y + 20 = 0

(y + 5) (y + 4) = 0

y = -5, -4

x > y

10) Answer: C

I) x = ∜65536 % of 450 – 12²+ 80

x = 16 % of 450 – 144 + 80

x = (16/100) * 450 – 144 + 80

x = 72 – 144 + 80 = 8

II) y³= 1728

y = 12

x < y