Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Prelims 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Simplification
Directions (Q. 1 – 5): What value should come in the place of question mark in the given questions?
1) √625 × √6241 – 768 × 3 + √15129 + 106 × 2 = ?
a) 10
b) 16
c) 9
d) 6
e) None of these
2) 37.5 % of 80 % of 730 + 160 % of 250 – ? = 120 % of 400
a) 129
b) 139
c) 149
d) 159
e) None of these
3) 3 (3/4) + 4(2/5) – 3(1/8) + 6(2/5) = ?
a) 11(17/40)
b) 9(17/40)
c) 10(17/40)
d) 13(17/40)
e) None of these
4) √841 × 3 + 120 % of 450 – 180 % of 780 + 60 % of 1800 = ?
a) 303
b) 310
c) 308
d) 290
e) None of these
5) ? – (5/9) of 8379 – 243 ÷ 3 + 162 = 24
a) 4504
b) 3856
c) 5278
d) 2912
e) None of these
Data Interpretation
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions.
Following table shows the total number of students and the percentage of girl students among them and the ratio of total number of students and teachers in 5 different schools.
6) Total number of boy students in school Q is what percentage of total number of boys in school S?
a) 60 %
b) 75 %
c) 90 %
d) 80 %
e) None of these
7) Find the ratio between the total number of girl students in School P to that of School R?
a) 15: 8
b) 21: 13
c) 34: 15
d) 52: 33
e) None of these
8) Find the difference between the total number of teachers in school Q to that of school T?
a) 15
b) 25
c) 10
d) 20
e) None of these
9) Find the total number of teachers in school P, R and S together?
a) 140
b) 120
c) 105
d) 130
e) None of these
10) Total number of students in school P is approximately what percentage more/less than the total number of students in school R?
a) 40 % less
b) 55 % less
c) 95 % more
d) 70 % more
e) 80 % more
Answers :
Directions (1-5) :
1) Answer: d)
√625 × √6241 – 768 × 3 + √15129 + 106 × 2 = ?
25 * 79 – 2304 + 123 + 212 = ?
6=?
2) Answer: b)
37.5 % of 80 % of 730 + 160 % of 250 – ? = 120 % of 400
219 + 400 – ? = 480
139 = ?
3) Answer: a)
3 (3/4) + 4(2/5) – 3(1/8) + 6(2/5) = ?
(3 + 4 – 3 + 6) (3/4 + 2/5 – 1/8 + 2/5) = ?
10(57/40) = ?
11(17/40) = ?
4) Answer: a)
√841 × 3 + 120 % of 450 – 180 % of 780 + 60 % of 1800 = ?
29 * 3 + 120/100 * 450 – 180/100 * 780 + 60/100 * 1800 =?
87 + 540 – 1404 + 1080 = ?
303 = ?
5) Answer: a)
? – (5/9) of 8379 – 243 ÷ 3 + 162 = 24
? – (5/9)*8379 – (243/3) + 256 = 24
? – 4655 – 81 + 256 = 24
? = 24 + 4655 + 81 – 256 = 4504
Directions (6-10) :
6) Answer: b)
Total number of boy students in school Q
= > 1500*(54/100) = 810
Total number of boys in school S
= > 1800*(60/100) = 1080
Required % = (810/1080)*100 = 75 %
7) Answer: d)
The total number of girl students in School P
= > 2000*(52/100) = 1040
The total number of girl students in School R
= > 1200*(55/100) = 660
Required ratio = 1040 : 660 = 52 : 33
8) Answer: c)
The total number of teachers in school Q
= > (1500/25) = 60
The total number of teachers in school T
= > (2400/48) = 50
Required difference = 60 – 50 = 10
9) Answer: a)
The total number of teachers in school P, R and S together
= > (2000/50) + (1200/24) + (1800/36)
= > 40 + 50 + 50 = 140
10) Answer: d)
Total number of students in school P = 2000
Total number of students in school R = 1200
Required % = [(2000 – 1200)/1200]*100 = 66.67 % = 70 % more
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