SBI Clerk Prelims 2020 Quantitative Aptitude Questions (Day-19)

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Approximation

Directions (Q. 1 – 5): what approximate value should come in place of question mark (?) in the following questions?

1) √(21609.28) ÷ 7.12 × 15.21 = ? – 16759 ÷ 9

a) 2850

b) 3435

c) 2180

d) 1965

e) 1350

2) (12.89)² + 48 % of 708 – (2/7) of 1224 = ? – (6.12)³

a) 370

b) 290

c) 210

d) 330

e) 425

3) 34484 ÷ 11 + (5/9) of 12149 + 56 % of 8978 = ?² – 451.32

a) 118

b) 132

c) 126

d) 130

e) 124

4) ? % of 502 – 8.21 % of 3011 – (3/8) of (2/3) of 71 = 23

a) 68

b) 44

c) 32

d) 56

e) 75

5) (17.77)² – (7/4) × 36 ÷ 9 + (3.12)³ = ? + (11.13)²

a) 185

b) 223

c) 162

d) 157

e) 140

Simplification

Directions (Q. 6 – 10): what value should come in place of question mark (?) in the following questions?

6) (3/8) of 2400 = 28 % of 1350 + (2/5) of (?)

a) 1305

b) 1780

c) 2156

d) 2378

e) None of these

7) (18)² ÷ 6 × 11 + 27² = 3 × ? – 45 % of 1500

a) 528

b) 632

c) 724

d) 666

e) None of these

8) 2080 ÷ (32 % of 250) = 36 × 5 7/9 of (? ÷ 104)

a) 18

b) 13

c) 24

d) 27

e) None of these

9) 221 ÷ 13 + (3/11) of 1155 + 27 % of 5400 = ?² – 235

a) 38

b) 52

c) 45

d) 26

e) None of these

10) (51110 ÷ 19) + (2/9) of 11565 + 26² = 40 % of ?

a) 9850

b) 17560

c) 21820

d) 14840

e) None of these

Answers :

Directions (1-5) :

1) Answer: c)

√(21609) ÷ 7 × 15 = x – 16758 ÷ 9

(147/7) * 15 = x – (16758/9)

315 + 1862 = x

x = 2177 = 2180

2) Answer: a)

13² + 48 % of 700 – (2/7) of 1225 = ? – 6³

169 + (48/100) * 700 – (2/7) * 1225 + 216 = x

x = 169 + 336 – 350 + 216 = 371

x = 370

3) Answer: e)

34485 ÷ 11 + (5/9) of 12150 + 56 % of 9000 = x² – 451

(34485/11) + (5/9) * 12150 + (56/100) * 9000 = x² – 451

3135 + 6750 + 5040 + 451 = x²

x² = 15376

x = 124

4) Answer: d)

x % of 500 – 8 % of 3000 – (3/8) of (2/3) of 72 = 23

x * (500/100) – (8/100) * 3000 – (3/8) * (2/3) * 72 = 23

5x – 240 – 18 = 23

5x = 23 + 240 + 18

5x = 281

x = 281/5 = 56

5) Answer: b)

18² – (7/4) × (36 ÷ 9) + 3³ = x + 11²

324 – 7 + 27 – 121 = x

x = 223

Ditections (6-10) :

6) Answer: a)

(3/8) * 2400 = (28/100) * 1350 + (2/5) * x

900 = 378 + 2x/5

900 – 378 = 2x/5

x = 522 * (5/2) = 1305

7) Answer: d)

(18 * 18 * 11)/6 + 729 = 3x – (45/100) * 1500

594 + 729 = 3x – 675

1998 = 3x

x = 1998/3 = 666

8) Answer: b)

2080 ÷ [(32/100) * 2150] = 36 * (52/9) * (x/104)

2080/80 = 2x

26 = 2x

x = 26/2 = 13

9) Answer: c)

(221/13) + (3/11) * 1155 + (27/100) * 5400 = x² – 235

17 + 315 + 1458 + 235 = x²

x² = 2025

x = 45

10) Answer: d)

(51110/19) + (2/9) * 11565 + 676 = (40/100) * x

2690 + 2570 + 676 = 4x/10

5936 = 4x/10

x = 5936 * (10/4) = 14840